更新1:
這個證明很容易看懂
5.5頁長
但有幾幅圖+double line spacing
所以實際長度=3頁...... 比佢證明到
都系個句: 數學界可以折埋.
更新2:
妳的解答未如滿意
請補充
更新3:
Andrew: good observation
but in his definition
he didn't say "every even number m"
only "for some m"
i.e. first he only consider the m such that p0 and pn are both prime.
看來「好怕Homework」冇仔細睇個proof. 其實個proof系Page 4
Def 1.1 就已經唔work. The last prime in the Goldbach block pn = m - p0 根本唔系壹個prime 楝壹個例子壹個even number 減 3唔系prime非常容易
例如12就唔得。 2008-02-29 00:47:16 補充： Eq 2.0 都唔掂啦，都冇define咩系p_(n+1) 2008-02-29 01:10:41 補充： The true problem is Corollary 1.1. The statement is for any prime p_a
r_a
r_t
p_q. If k-(p_a + r_a + r_t) = p_q
then p_q + (k - p_q) is a goldbach partition. 2008-02-29 01:10:46 補充： However
the proof requires p_a + r_a + r_t to be a prime number to start with
which is not stated as an assumption for the corollary. Check the usage on the last page
the use of corollary do not check the unstated assumption as well.
參考: 從不抄襲。
我表面看上去這個proof是倒果為因。他能夠找到個模式是因為哥德巴哈猜想好可能是對的﹐而他就倒過來說可以用這個方法找到每壹個偶數的2個對應質數。andrew大概講中了重點