1)先求Vb=VccxRb2/(Rb1+Rb2)=12x10K/(30K+10K)=3V
Ve=Vb-0.6=3-0.6=2.4V
Ie=Ve/(Re1+Re2)=2.4/1.2K=2mA
Ib=Ie/(β+1)≈0.02mA
Vce=12-Ie(Re1+Re2+Rc)=12-2x4.2=3.6V
2)見附圖
3)rbe=rbb`+(1+β)26mV/Ie=300+26mV/0.02=1600Ω
Ri=Rb1//Rb2//rbe=10K//30K//1.6K=1.3K Ro=Rc=3K Av=-βxRc//RL/[rbe+(1+β)Re1]=-100x0.75k/(1.6K+20.2K)=-3.44